3(x^2+1)-x=2x+9

Solution for 3(x^2+1)-x=2x+9 equation:

3(x^2+1)-x=2x+9

We move all terms to the left:

3(x^2+1)-x-(2x+9)=0

We add all the numbers together, and all the variables

-1x+3(x^2+1)-(2x+9)=0

We multiply parentheses

3x^2-1x-(2x+9)+3=0

We get rid of parentheses

3x^2-1x-2x-9+3=0

We add all the numbers together, and all the variables

3x^2-3x-6=0

a = 3; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·3·(-6)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-9}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+9}{2*3}=\frac{12}{6}
=2
$